216^(x+1)=(1/1296)^x+2

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Solution for 216^(x+1)=(1/1296)^x+2 equation: 



216^(x+1)=(1/1296)^x+2

We move all terms to the left:

216^(x+1)-((1/1296)^x+2)=0



Domain of the equation: 1296)^x+2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

216^(x+1)-((+1/1296)^x+2)=0

We multiply all the terms by the denominator


(216^(x+1))*1296)^x+2)-((+1=0

We move all terms containing x to the left, all other terms to the right

(216^(x+1))*1296)^x+2)-((=-1

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